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100x^2+3=28
We move all terms to the left:
100x^2+3-(28)=0
We add all the numbers together, and all the variables
100x^2-25=0
a = 100; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·100·(-25)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100}{2*100}=\frac{-100}{200} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100}{2*100}=\frac{100}{200} =1/2 $
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